Question

question 23 (1 point)
if the resistance in a circuit with constant current flowing is doubled, the power dissipated by that circuit will
quadruple.
double.
decrease to one half.
decrease to one fourth.
short answers
question 24 (6 points)
an object is pushed from rest across a sheet of ice, accelerating at 5.0 m/s² over a distance of

Explanation:

Step1: Recall the power formula for a circuit with current \( I \) and resistance \( R \)

The formula for power dissipated in a circuit is \( P = I^2R \), where \( I \) is the current and \( R \) is the resistance.

Step2: Analyze the change in resistance

We are given that the current \( I \) is constant, and the resistance \( R \) is doubled. Let the initial resistance be \( R_1 = R \) and the new resistance be \( R_2 = 2R \). The initial power is \( P_1 = I^2R_1 = I^2R \), and the new power is \( P_2 = I^2R_2 \).
Substitute \( R_2 = 2R \) into the power formula for the new power: \( P_2 = I^2(2R) = 2I^2R \).
But we know that \( P_1 = I^2R \), so \( P_2 = 2P_1 \). This means when the resistance is doubled (with constant current), the power doubles.

Answer:

double. (The option corresponding to this is the one with "double" as the text, e.g., if the options are as in the image, the correct option is the one labeled with "double".)