Question

question 6 of 25
how much electrical potential energy is stored in a capacitor that has 8.0×10^(-10) c of charge on each plate and a potential difference across the plates of 40.0 v? (use pe_e = 1/2 qδv)
a. 3.2×10^(-8) j
b. 8.0×10^(-9) j
c. 4.0×10^(-9) j
d. 1.6×10^(-8) j

Explanation:

Step1: Identify given values

$Q = 8.0\times10^{-10}\text{ C}$, $V = 40.0\text{ V}$

Step2: Substitute values into formula

$PE_e=\frac{1}{2}QV=\frac{1}{2}\times(8.0\times 10^{-10}\text{ C})\times40.0\text{ V}$

Step3: Calculate the result

$PE_e=\frac{1}{2}\times8.0\times 10^{-10}\times40.0\text{ J}= 1.6\times 10^{-8}\text{ J}$

Answer:

D. $1.6\times 10^{-8}\text{ J}$