Question

question 26 of 40
which triangle results from a reflection across the line $x=1$?

Explanation:

Step1: Identify original triangle vertices

Original vertices: $A(1,2)$, $B(4,2)$, $C(2,4)$

Step2: Apply reflection formula for $x=1$

For a point $(x,y)$, reflection over $x=a$ is $(2a-x,y)$. Here $a=1$, so formula is $(2(1)-x,y)=(2-x,y)$.

• Reflect $A$: $A'(2-1,2)=(1,2)$
• Reflect $B$: $B'(2-4,2)=(-2,2)$
• Reflect $C$: $C'(2-2,4)=(0,4)$

Step3: Match to options

The reflected vertices $(1,2), (-2,2), (0,4)$ correspond to Option B.

Answer:

B. <The triangle with vertices at (1,2), (-2,2), (0,4)>