Question

question 26
1 pts
there are ______ orbitals in the third shell.
9
25
16
1
4
question 27
1 pts
ar4s²3d¹⁰4p³ is the electron configuration of a(n) ______ atom.
sb
sn
as
p
v

Explanation:

Step1: Recall orbital - counting formula

The number of orbitals in a shell with principal quantum number \(n\) is given by \(n^{2}\). For the third shell, \(n = 3\).

Step2: Calculate number of orbitals

Substitute \(n = 3\) into the formula \(n^{2}\). So, \(3^{2}=9\).

Step3: Analyze electron - configuration for Question 27

The electron - configuration \([Ar]4s^{2}3d^{10}4p^{3}\) means the atom has the electron configuration of argon (\(Ar\), which has 18 electrons) plus \(2 + 10+3=15\) more electrons. So the total number of electrons is \(18 + 15=33\).

Step4: Identify the element

The element with 33 electrons has an atomic number of 33, which is arsenic (\(As\)).

Answer:

Question 26: A. 9
Question 27: C. As