Question

question 1 of 30 what is the volume of 0.24 mol oxygen (o₂) gas at 345 k and a pressure of 0.75 atm? (the universal gas constant is 0.0821 l·atm/mol·k.) a. 89 l b. 0.11 l c. 5.1 l d. 9.1 l

Explanation:

Step1: Recall Ideal Gas Law

The ideal gas law is \( PV = nRT \), where \( P \) is pressure, \( V \) is volume, \( n \) is moles, \( R \) is gas constant, \( T \) is temperature. We need to solve for \( V \), so rearrange the formula: \( V=\frac{nRT}{P} \).

Step2: Substitute Values

Given \( n = 0.24\space mol \), \( R = 0.0821\space L\cdot atm/mol\cdot K \), \( T = 345\space K \), \( P = 0.75\space atm \). Substitute into the formula:
\( V=\frac{0.24\space mol\times0.0821\space L\cdot atm/mol\cdot K\times345\space K}{0.75\space atm} \)
First, calculate the numerator: \( 0.24\times0.0821\times345 = 0.24\times28.3245 = 6.79788 \)
Then divide by the denominator: \( V=\frac{6.79788}{0.75}\approx9.1\space L \)

Answer:

D. 9.1 L