Question

question 5 of 30
which substance will form a solution when mixed with solid sodium chloride?

a. nao₂(s)

b. ccl₄(l)

c. cl₂(g)

d. ch₃oh(l)

Explanation:

Sodium chloride ($\ce{NaCl}$) is an ionic compound. For a substance to form a solution with $\ce{NaCl}$, it should be a polar solvent (like dissolves like principle: ionic compounds dissolve well in polar solvents).

• Option A: $\ce{NaO_{2}(s)}$ is a solid ionic compound, mixing two solids won't form a solution.
• Option B: $\ce{CCl_{4}(l)}$ is a non - polar solvent (tetrachloromethane), non - polar solvents don't dissolve ionic compounds well.
• Option C: $\ce{Cl_{2}(g)}$ is a non - polar gas, it won't dissolve ionic $\ce{NaCl}$ to form a solution.
• Option D: $\ce{CH_{3}OH(l)}$ (methanol) is a polar solvent (has a polar $\ce{-OH}$ group). Ionic $\ce{NaCl}$ can dissolve in polar methanol to form a solution.

Answer:

D. $\ce{CH_{3}OH}(l)$