Question

question 37 (1 point) saved a soft drink company holds a contest in which a prize may be revealed on the inside of the bottle cap. the probability that each bottle cap reveals a prize is 0.2 and winning is independent from one bottle to the next. what is the probability that a customer must open three or more bottles before winning a prize? (0.2)(0.2)(0.8)=0.032 (0.8)(0.8)(0.2)=0.128 (0.8)(0.8)=0.64 1 - (0.2)(0.2)(0.8)=.968

Explanation:

Step1: Identify non - winning and winning probabilities

The probability of not winning on a single bottle is $0.8$ and the probability of winning is $0.2$.

Step2: Calculate probability of not winning in first two bottles

Since the events are independent, the probability of not winning in the first two bottles is $(0.8)\times(0.8)= 0.64$.

Answer:

$(0.8)(0.8)=0.64$