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Question
question
a boat heading out to sea starts out at point $a$, at a horizontal distance of 1315 feet from a lighthouse/the shore. from that point, the boats crew measures the angle of elevation to the lighthouses beacon-light from that point to be $12^{\circ}$. at some later time, the crew measures the angle of elevation from point $b$ to be $8^{\circ}$. find the distance from point $a$ to point $b$. round your answer to the nearest foot if necessary.
answer attempt 1 out of 2
feet
Step1: Find height of lighthouse
Let $h$ = height of lighthouse. Use $\tan(\theta)=\frac{\text{opposite}}{\text{adjacent}}$ for Point A.
$\tan(12^\circ)=\frac{h}{1315}$
$h = 1315 \times \tan(12^\circ)$
Calculate: $h \approx 1315 \times 0.2126 = 279.569$ feet
Step2: Find distance from shore to Point B
Use the height $h$ to find horizontal distance $d_B$ from shore to B.
$\tan(8^\circ)=\frac{h}{d_B}$
$d_B = \frac{h}{\tan(8^\circ)}$
Calculate: $d_B \approx \frac{279.569}{0.1405} = 1989.815$ feet
Step3: Find distance A to B
Subtract distance from shore to A from distance to B.
$AB = d_B - 1315$
$AB \approx 1989.815 - 1315 = 674.815$
Step4: Round to nearest foot
Round the result to whole number.
$AB \approx 675$
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675 feet