Question

question
brandon and jace are reading the same book. at the beginning of the month, brandon was on page 16 and jace was on page 48. brandon will read 11 pages per day, and jace will read 3 pages per day. let b represent the page of the book that brandon is on at the end of t days into the month, and let j represent the page of the book that jace is on at the end of t days into the month. write an equation for each situation, in terms of t, and determine whether brandon or jace is farther along in the book after 2 days.
answer attempt 1 out of 2
b =
j =
will be pages farther along in the book than after 2 days.
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Explanation:

Step1: Define Brandon's page equation

Brandon starts at page 16 and reads 11 pages per day. So the number of pages he is on after \( t \) days is initial page plus pages read.
\( B = 16 + 11t \)

Step2: Define Jace's page equation

Jace starts at page 48 and reads 3 pages per day. So the number of pages he is on after \( t \) days is initial page plus pages read.
\( J = 48 + 3t \)

Step3: Calculate for \( t = 2 \) days (Brandon)

Substitute \( t = 2 \) into Brandon's equation:
\( B = 16 + 11\times2 = 16 + 22 = 38 \)

Step4: Calculate for \( t = 2 \) days (Jace)

Substitute \( t = 2 \) into Jace's equation:
\( J = 48 + 3\times2 = 48 + 6 = 54 \)

Step5: Compare \( B \) and \( J \) at \( t = 2 \)

Find the difference: \( 54 - 38 = 16 \). So Jace is farther.

Answer:

\( B = 16 + 11t \), \( J = 48 + 3t \); Jace will be 16 pages farther along in the book than Brandon after 2 days.