Question

question
distribute $-7\left(-9x^{2} + 3x\
ight)$.

Explanation:

Step1: Apply distributive property

The distributive property states that \(a(b + c)=ab+ac\). So for \(-7(-9x^{2}+3x)\), we distribute \(-7\) to each term inside the parentheses:
\(-7\times(-9x^{2})+(-7)\times(3x)\)

Step2: Multiply the coefficients

First, calculate \(-7\times(-9x^{2})\). The product of two negative numbers is positive, and \(7\times9 = 63\), so \(-7\times(-9x^{2})=63x^{2}\).
Then, calculate \((-7)\times(3x)\). The product of a negative and a positive number is negative, and \(7\times3 = 21\), so \((-7)\times(3x)=- 21x\).

Step3: Combine the results

Combining the two terms we got from the previous step, we have \(63x^{2}-21x\).

Answer:

\(63x^{2}-21x\)