Question

question
factor.
$x^2 + 3x - 18$

Explanation:

Step1: Find two numbers

We need two numbers that multiply to -18 and add up to 3. The numbers are 6 and -3 since \(6\times(-3)= - 18\) and \(6+( - 3)=3\).

Step2: Factor the quadratic

Using the numbers found, we can factor the quadratic \(x^{2}+3x - 18\) as \((x + 6)(x-3)\).

Answer:

\((x + 6)(x - 3)\)