Question

question
factor.
$x^2 - 14x + 45$

Explanation:

Step1: Find two numbers

We need two numbers that multiply to \(45\) and add up to \(-14\) (since the middle term is \(-14x\) and the constant term is \(45\)). The numbers are \(-5\) and \(-9\) because \((-5)\times(-9) = 45\) and \((-5)+(-9)=-14\).

Step2: Factor the quadratic

Using the two numbers, we can factor the quadratic \(x^{2}-14x + 45\) as \((x - 5)(x - 9)\).

Answer:

\((x - 5)(x - 9)\)