Question

question
factor completely.
$x^3 + 4x^2 - 14x - 56$

Explanation:

Step1: Group terms in pairs

$x^3 + 4x^2 - 14x - 56 = (x^3 + 4x^2) + (-14x - 56)$

Step2: Factor out GCF from each pair

$(x^3 + 4x^2) + (-14x - 56) = x^2(x + 4) - 14(x + 4)$

Step3: Factor out common binomial

$x^2(x + 4) - 14(x + 4) = (x + 4)(x^2 - 14)$

Answer:

$(x + 4)(x^2 - 14)$