Question

question
find the distance between the two points rounding to the nearest tenth (if necessary).
(-6, -4) and (-4, 2)

Explanation:

Step1: Recall distance formula

The distance formula between two points $(x_1,y_1)$ and $(x_2,y_2)$ is $d = \sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}$. Here, $x_1=-6$, $y_1 = - 4$, $x_2=-4$, $y_2 = 2$.

Step2: Substitute values

$d=\sqrt{(-4-(-6))^2+(2 - (-4))^2}=\sqrt{( - 4 + 6)^2+(2 + 4)^2}=\sqrt{2^2+6^2}$.

Step3: Calculate squares and sum

$\sqrt{2^2+6^2}=\sqrt{4 + 36}=\sqrt{40}$.

Step4: Simplify and round

$\sqrt{40}\approx6.3$ (rounded to the nearest tenth).

Answer:

$6.3$