Question

question
go step by step to reduce the radical.
$\frac{sqrt{240}}{sqrt{16} cdot sqrt{15}}$
$squaresqrt{square}$
try
answer attempt 1 out of 2
you must answer all questions above in order to submit.

Explanation:

Step1: Factor 240 into perfect square

$\sqrt{240} = \sqrt{16 \times 15}$

Step2: Split radical using product rule

$\sqrt{16 \times 15} = \sqrt{16} \cdot \sqrt{15}$

Step3: Simplify $\sqrt{16}$

$\sqrt{16} = 4$

Step4: Combine to get final form

$4\sqrt{15}$

Answer:

$4\sqrt{15}$