Question

question 2
graph the line through the points (-6,2) and (6,-6).
write an equation of the line in the form y = mx + b.
y=
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Explanation:

Step1: Calculate the slope $m$.

The slope formula is $m=\frac{y_2 - y_1}{x_2 - x_1}$. Let $(x_1,y_1)=(-6,2)$ and $(x_2,y_2)=(6,-6)$. Then $m=\frac{-6 - 2}{6-(-6)}=\frac{-8}{12}=-\frac{2}{3}$.

Step2: Find the y - intercept $b$.

Use the point - slope form $y - y_1=m(x - x_1)$ with the point $(-6,2)$ and $m =-\frac{2}{3}$. So $y - 2=-\frac{2}{3}(x + 6)$. Expand the right side: $y-2=-\frac{2}{3}x-4$. Add 2 to both sides to get the slope - intercept form $y=-\frac{2}{3}x-2$.

Answer:

$y =-\frac{2}{3}x - 2$