Question

question 6
if (int_{-3}^{8} h(s) ds = 7) and (int_{4}^{8} h(s) ds = 4.4) what does the following integral equal?(int_{-3}^{4} h(s) ds =)

Explanation:

Step1: Apply integral interval addition rule

Recall that $\int_{a}^{c} h(s)ds = \int_{a}^{b} h(s)ds + \int_{b}^{c} h(s)ds$ for $a < b < c$. Rearranged, this gives $\int_{a}^{b} h(s)ds = \int_{a}^{c} h(s)ds - \int_{b}^{c} h(s)ds$.

Step2: Substitute given integral values

Substitute $\int_{-3}^{8} h(s)ds = 7$, $\int_{4}^{8} h(s)ds = 4.4$ into the formula:
$\int_{-3}^{4} h(s)ds = 7 - 4.4$

Step3: Calculate the result

Perform the subtraction:
$7 - 4.4 = 2.6$

Answer:

2.6