Question

question 4 (multiple choice worth 1 points) (03.05r mc) if △efg ~ △lmn with a ratio of 4:1, which of the following is true? (\frac{overline{ef}}{overline{lm}}=\frac{overline{fg}}{overline{ln}}) (overline{ef}equivoverline{lm}) (\frac{overline{ef}}{overline{lm}}=\frac{overline{fg}}{overline{mn}}) (overline{eg}equivoverline{lm})

Explanation:

Step1: Recall property of similar triangles

For similar triangles $\triangle EFG\sim\triangle LMN$ with a ratio of $a:b$, the ratios of corresponding - side lengths are equal. That is, if $\triangle EFG\sim\triangle LMN$, then $\frac{EF}{LM}=\frac{FG}{MN}=\frac{EG}{LN}$.

Answer:

$\frac{\overline{EF}}{\overline{LM}}=\frac{\overline{FG}}{\overline{MN}}$ (the option with $\frac{EF}{LM}=\frac{FG}{MN}$)