Question

question 5 (multiple choice worth 2 points) (transformations of linear functions mc) given that $h(x) = g(x) - 4$ is a transformation of $g(x)$, determine $h(x)$ for $x = 0$. \

$$\begin{tabular}{|l|l|l|l|} \\hline $x$ & 0 & 3 & 5 \\\\ \\hline $g(x)$ & $-5$ & 16 & 30 \\\\ \\hline \\end{tabular}$$

options: $-4$, $-9$

Explanation:

Step1: Find \( g(0) \) from the table

From the table, when \( x = 0 \), \( g(0)=-5 \).

Step2: Use the transformation \( h(x)=g(x)-4 \) to find \( h(0) \)

Substitute \( x = 0 \) into \( h(x) \): \( h(0)=g(0)-4 \).
Substitute \( g(0)=-5 \) into the equation: \( h(0)=-5 - 4=-9 \).

Answer:

\(-9\)