Question

question number 14. the decline of salmon fisheries along the columbia river in oregon has caused great concern among commercial and recreational fishermen. the juvenile salmonids in john day reservoir, columbia river (trans. amer. fisheries soc. (1991:405 - 420)) gave the accompanying data on y = maximum size of salmonids consumed by a northern squawfish (the most abundant salmonid predator) and x = squawfish length, both in mm. here is the computer software printout of the summary. coefficients: (intercept) estimate -91.030 std. error 16.713 t value -5.447 pr(>|t|) 0.000 length estimate 0.710 std. error 0.048 t value 14.730 pr(>|t|) 0.000 using this information, give the equation of the least squares regression line. 〇ŷ=-91.030x + 0.710 〇ŷ=16.713x + 0.048 〇ŷ=16.713x - 91.030 〇ŷ=0.710x + 16.713 〇ŷ=0.710x - 91.030 none of the above

Explanation:

Step1: Recall regression - line formula

The least - squares regression line has the form $\hat{y}=b_0 + b_1x$, where $b_0$ is the intercept and $b_1$ is the slope.

Step2: Identify coefficients from table

From the table, the intercept estimate $b_0=-91.030$ and the slope estimate $b_1 = 0.710$.

Step3: Write the regression line equation

The least - squares regression line is $\hat{y}=-91.030 + 0.710x$.

Answer:

$\hat{y}=0.710x - 91.030$