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Question
question 4 (1 point)
assign oxidation numbers to agno₃.
ag -
n -
o -
Step1: Recall oxidation - number rules
Oxidation number of oxygen is usually - 2 and for a neutral compound, the sum of oxidation numbers of all atoms is 0.
Step2: Find oxidation number of O
Oxygen has an oxidation number of - 2 in most compounds. In $AgNO_3$, there are 3 oxygen atoms, so the total contribution from oxygen is $3\times(- 2)=-6$.
Step3: Find oxidation number of Ag
Silver (Ag) is a monovalent metal in this compound and has an oxidation number of + 1.
Step4: Calculate oxidation number of N
Let the oxidation number of N be $x$. Since the sum of oxidation numbers in $AgNO_3$ is 0, we have $(+1)+x+(-6) = 0$. Solving for $x$ gives $x=+5$.
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Ag - +1, N - +5, O - -2