Question

question 1 · 1 point
find the derivative of
$y = (\frac{4x - 2}{2x - 1})^3$
you should leave your answer in factored form. do not include \$h(x)=$\ in your answer.
provide your answer below:

Explanation:

Step1: Use product - rule and chain - rule

Let $u=(2x - 1)$ and $v = (\frac{4x-2}{2x - 1})^3$. First, simplify $\frac{4x-2}{2x - 1}=2$. So $y=(2x - 1)\times2^3=8(2x - 1)$.

Step2: Differentiate

$y'=8\times2 = 16$.

Answer:

$16$