Question

question 4 (1 point) listen how many atoms are in 0.534 mol of nickel, ni? a) $2.44 \times 10^{22}$ atoms b) $6.98 \times 10^{21}$ atoms c) $3.22 \times 10^{23}$ atoms d) $1.13 \times 10^{24}$ atoms e) $1.48 \times 10^{25}$ atoms

Explanation:

Step1: Recall Avogadro's number

Avogadro's number is $N_A = 6.022 \times 10^{23}\ \text{atoms/mol}$

Step2: Calculate number of atoms

Multiply moles by Avogadro's number:
$\text{Number of atoms} = 0.534\ \text{mol} \times 6.022 \times 10^{23}\ \text{atoms/mol}$
$\text{Number of atoms} = 0.534 \times 6.022 \times 10^{23}$
$\text{Number of atoms} \approx 3.22 \times 10^{23}$

Answer:

c) $3.22 \times 10^{23}$ atoms