Question

question 6 (1 point) listen how many moles are in $8.73 \times 10^{25}$ atoms of boron, b? a) $5.04 \times 10^{-25}$ moles b) 1.45 moles c) $6.90 \times 10^{-3}$ moles d) 145 moles e) $3.84 \times 10^{27}$ moles

Explanation:

Step1: Use Avogadro's number conversion

Recall that 1 mole = $6.022 \times 10^{23}$ atoms. To find moles, divide total atoms by Avogadro's number:
$\text{Moles of B} = \frac{8.73 \times 10^{25}}{6.022 \times 10^{23}}$

Step2: Calculate the result

First compute the coefficient: $\frac{8.73}{6.022} \approx 1.45$
Then compute the exponents: $10^{25-23} = 10^{2}$
Multiply together: $1.45 \times 10^{2} = 145$

Answer:

d) 145 moles