Question

question 5 (1 point)
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which of the following is the correct electron configuration for pd²⁺?
a) kr4d⁸
b) kr5s²4d¹⁰
c) kr4d¹⁰
d) kr5s²4d⁶
e) kr5s²4d⁸

Explanation:

Step1: Determine Pd's atomic number

Palladium (Pd) has an atomic number of 46. Its neutral - atom electron configuration is [Kr]4d^{10} (a special case where the 5s orbital is empty and the 4d orbital is filled).

Step2: Consider the ion formation

When Pd forms a Pd^{2 +} ion, it loses 2 electrons. Since the neutral Pd has an unusual electron configuration of [Kr]4d^{10}, losing 2 electrons from the out - most orbitals (in this case, we can consider the "outer" electrons in the 4d system for the + 2 ion formation), the electron configuration of Pd^{2+} remains [Kr]4d^{8}.

Answer:

a) [Kr]4d^{8}