Question

question 9 (1 point) na-24 undergoes beta decay. what is the resulting nuclide? a mg-24 b mg-25 c ne-24 d ne-25

Explanation:

Step1: Recall beta - decay equation

In beta - decay, a neutron in the nucleus is converted into a proton, an electron, and an antineutrino. The atomic number (Z) increases by 1 while the mass number (A) remains the same.

Step2: Identify initial nuclide properties

Sodium (Na) has an atomic number Z = 11 and for Na - 24, the mass number A=24.

Step3: Calculate properties of resulting nuclide

After beta - decay, the atomic number becomes Z = 11 + 1=12, and the mass number remains A = 24. The element with atomic number 12 is magnesium (Mg). So the resulting nuclide is Mg - 24.

Answer:

A. Mg-24