Question

question 1 (1 point)
a rectangle has a length that is 3 more than twice the width. its perimeter is 96 inches.
which equation models this?
a 2w + 3 = 96
b w + 2w + 3 = 96
c 2(w)+2(w + 3)=96
d 2(w)+2(2w + 3)=96

Explanation:

Step1: Define variables

Let the width of the rectangle be $w$. The length $l$ is 3 more than twice the width, so $l = 2w+3$.

Step2: Recall perimeter formula

The perimeter $P$ of a rectangle is given by $P = 2l+2w$.

Step3: Substitute length into perimeter formula

Substitute $l = 2w + 3$ into $P=2l + 2w$. We get $P=2(2w + 3)+2w$. Since $P = 96$, the equation is $2(2w+3)+2w=96$.

Answer:

D. $2(w)+2(2w + 3)=96$