Question

question 9 (1 point) solve the inequality. \\(\frac{k}{-3} \geq 7\\) \\(\circ\\) a \\(k \leq -21\\) \\(\circ\\) b \\(k \geq -21\\) \\(\circ\\) c \\(k \geq 10\\)

Explanation:

Step1: Multiply both sides by -3

When multiplying or dividing an inequality by a negative number, the direction of the inequality sign flips. So, we multiply both sides of $\frac{k}{-3} \geq 7$ by -3:
$$\frac{k}{-3} \times (-3) \leq 7 \times (-3)$$

Step2: Simplify both sides

Simplifying the left side gives $k$, and simplifying the right side gives $-21$. So we have:
$$k \leq -21$$

Answer:

A. \( k \leq -21 \)