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Question
question 1 (5 points) taking a cruise is a costly discretionary expense. in a recent year, the top five cruise lines in the world had the following number of passengers: 4,133,000 2,369,000 1,295,000 928,000 679,000 what is the mean number of passengers for these 5 cruise lines? round your answers to the nearest integer. use commas like the data points above, or the computer will mark it as incorrect. blank 1:
Step1: Recall mean formula
The mean $\bar{x}=\frac{\sum_{i = 1}^{n}x_{i}}{n}$, where $x_{i}$ are data - points and $n$ is the number of data - points. Here, $n = 5$, and $x_1=4133000$, $x_2 = 2369000$, $x_3=1295000$, $x_4 = 928000$, $x_5=679000$.
Step2: Calculate the sum of data - points
$\sum_{i = 1}^{5}x_{i}=4133000 + 2369000+1295000 + 928000+679000=9404000$.
Step3: Calculate the mean
$\bar{x}=\frac{9404000}{5}=1880800$.
Step4: Round to the nearest integer
Rounding $1880800$ to the nearest integer (it is already an integer), we get $1880800$.
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$1880800$