Question

question 9
0.1 pts
how many grams are in 5.18 x 10^-4 moles of \d\? input the numeric value.
a.ca3(po3)2 b. k2s c. ga(oh)3 d. sr3(po4)2 e. k2o f. al(oh)3
g. cu2so3 hk2co3 i. hnaso4 j. rb2co3 k.hkso4 l. ca3(po4)2

Explanation:

Step1: Calculate molar mass of $Sr_3(PO_4)_2$

$M_{Sr}=87.62\ g/mol$, $M_{P}=30.97\ g/mol$, $M_{O}=16.00\ g/mol$.
$M = 3\times87.62+2\times(30.97 + 4\times16.00)$
$=262.86+2\times(30.97 + 64.00)$
$=262.86+2\times94.97$
$=262.86 + 189.94$
$=452.8\ g/mol$

Step2: Calculate mass from moles

Use the formula $m = n\times M$, where $n = 5.18\times10^{-4}\ mol$ and $M = 452.8\ g/mol$.
$m=5.18\times10^{-4}\times452.8$
$m = 0.2345504\ g$

Answer:

$0.2345504$