Question

question 1 1 pts how does the noble gas configuration shorten the electron configuration? by putting the previous element in front of the remaining configuration nothing changes by putting the previous noble gas in front of the remaining configuration by putting the next noble gas in front of the remaining configuration

Explanation:

To determine how noble gas configuration shortens electron configuration, recall the concept: Noble gas configuration uses the electron configuration of the previous (or preceding) noble gas (which has a full valence shell) and then writes the remaining electron configuration for the element. For example, for sodium (Na, atomic number 11), the electron configuration is $1s^2 2s^2 2p^6 3s^1$. The previous noble gas is neon (Ne, electron configuration $1s^2 2s^2 2p^6$), so Na’s noble gas configuration is $[Ne] 3s^1$.

• The first option is incorrect because it says “previous element” (not noble gas).
• The second option is incorrect as noble gas configuration does shorten it.
• The fourth option is incorrect because we use the previous (not next) noble gas (next noble gas would have a higher atomic number and more electrons, which is not correct for shortening).
• The third option matches the definition: we put the previous noble gas (with its configuration) in brackets in front of the remaining electron configuration.

Answer:

C. By putting the previous noble gas in front of the remaining configuration (assuming the options are labeled A, B, C, D with C being the third option as described)