Question

question solve for x and graph the solution on the number line below. 12 ≥ -x + 9 and 6 ≤ -x + 9 answer attempt 1 out of 2 < > ≤ ≥ or inequality notation: number line: -12 -10 -8 -6 -4 -2 0 2 4 6 8 10 12 click and drag to plot line. submit answer

Explanation:

Step1: Solve the first - inequality

Subtract 9 from both sides of $12\geq - x + 9$.
$12-9\geq - x+9 - 9$, which simplifies to $3\geq - x$. Multiply both sides by - 1 and reverse the inequality sign, we get $x\geq - 3$.

Step2: Solve the second - inequality

Subtract 9 from both sides of $6\leq - x + 9$.
$6 - 9\leq - x+9 - 9$, which simplifies to $-3\leq - x$. Multiply both sides by - 1 and reverse the inequality sign, we get $x\leq3$.

Answer:

Inequality Notation: $-3\leq x\leq3$
Number - Line: Plot a closed circle at - 3 and 3 on the number line and draw a line segment connecting them.