Question

question in △tuv, u = 180 cm, t = 820 cm and ∠u = 33°. find the area of △tuv, to the nearest square centimeter. answer attempt 1 out of 2 cm² submit answer watch video show examples

Explanation:

Step1: Recall the area formula for a triangle

The area formula for a triangle given two - sides and the included angle is $A=\frac{1}{2}tu\sin U$.

Step2: Substitute the given values

We are given that $t = 820$ cm, $u=180$ cm, and $U = 33^{\circ}$. Substitute these values into the formula: $A=\frac{1}{2}\times820\times180\times\sin(33^{\circ})$.

Step3: Calculate $\sin(33^{\circ})$

We know that $\sin(33^{\circ})\approx0.5446$.

Step4: Calculate the area

$A=\frac{1}{2}\times820\times180\times0.5446$. First, $\frac{1}{2}\times820\times180 = 410\times180=73800$. Then, $A = 73800\times0.5446\approx40291$.

Answer:

$40291$ cm²