Question

question
two sides of a parallelogram are 9.3 feet and 4.4 feet. the measure of the angle between these sides is 53°. find the area of the parallelogram to the nearest 10th of a square foot.

Explanation:

Step1: Recall area formula for parallelogram

The area $A$ of a parallelogram with sides $a$, $b$ and included angle $\theta$ is $A = a \cdot b \cdot \sin(\theta)$.

Step2: Substitute given values

Here, $a = 9.3$ ft, $b = 4.4$ ft, $\theta = 53^\circ$.
$A = 9.3 \times 4.4 \times \sin(53^\circ)$
First calculate $9.3 \times 4.4 = 40.92$. Then $\sin(53^\circ) \approx 0.7986$.

Step3: Compute final area

$A \approx 40.92 \times 0.7986 \approx 32.7$

Answer:

32.7 square feet