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question 6
the vertices of abc have coordinates a(-2,0), b(10,0), and c(4,4). determine the area of abc. (hint... use desmos!)
Step1: Identify base length
Points $A(-2,0)$ and $B(10,0)$ lie on the x-axis. The length of $AB$ is the difference in x-coordinates:
$AB = 10 - (-2) = 12$
Step2: Identify height of triangle
The height is the vertical distance from point $C(4,4)$ to the base $AB$ (x-axis), which is the y-coordinate of $C$:
$\text{Height} = 4$
Step3: Calculate triangle area
Use the area formula for a triangle: $\text{Area} = \frac{1}{2} \times \text{base} \times \text{height}$
$\text{Area} = \frac{1}{2} \times 12 \times 4$
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