Question

question
what is the area, in square feet, of the isosceles trapezoid below?
6.2 ft
8 ft
15.4 ft
answer attempt 1 out of 2
$a = \boldsymbol{\phantom{0000000000}}$ $\text{ft}^2$
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Explanation:

Step1: Recall trapezoid area formula

The area of a trapezoid is given by $A = \frac{1}{2}(b_1 + b_2)h$, where $b_1$ and $b_2$ are the lengths of the two parallel sides, and $h$ is the height.

Step2: Identify given values

Here, $b_1 = 6.2$ ft, $b_2 = 15.4$ ft, $h = 8$ ft.

Step3: Sum the parallel sides

$b_1 + b_2 = 6.2 + 15.4 = 21.6$ ft

Step4: Multiply by height and 1/2

$A = \frac{1}{2} \times 21.6 \times 8$
First calculate $\frac{1}{2} \times 21.6 = 10.8$, then $10.8 \times 8 = 86.4$

Answer:

86.4