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Question
question what is the sum of the interior angles of an 11 - gon? answer attempt 1 out of 2
Step1: Recall the formula
The formula for the sum of interior - angles of a polygon is $S=(n - 2)\times180^{\circ}$, where $n$ is the number of sides of the polygon.
Step2: Substitute $n = 11$
Substitute $n = 11$ into the formula: $S=(11 - 2)\times180^{\circ}$.
Step3: Calculate the result
First, calculate $11−2 = 9$. Then, $S=9\times180^{\circ}=1620^{\circ}$.
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$1620^{\circ}$