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Question
question
what is the sum of the interior angles of a 16 - gon?
answer attempt 1 out of 2
Step1: Recall the formula for the sum of interior angles of a polygon
The formula for the sum of the interior angles of a polygon with \( n \) sides is \( S=(n - 2)\times180^{\circ} \).
Step2: Identify the number of sides \( n \) for a 16 - gon
For a 16 - gon, the number of sides \( n = 16 \).
Step3: Substitute \( n = 16 \) into the formula
Substitute \( n = 16 \) into the formula \( S=(n - 2)\times180^{\circ} \). We get \( S=(16 - 2)\times180^{\circ} \).
Step4: Calculate the value
First, calculate \( 16-2 = 14 \). Then, multiply \( 14\times180^{\circ} \). \( 14\times180^{\circ}=2520^{\circ} \).
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The sum of the interior angles of a 16 - gon is \( 2520^{\circ} \)