Question

question
when lauren goes bowling, her scores are normally distributed with a mean of 105 and a standard deviation of 10. using the empirical rule, what percentage of the games that lauren bowls does she score between 95 and 115?

Explanation:

Step1: Identify z-scores for values

For 95: $z = \frac{95 - 105}{10} = -1$
For 115: $z = \frac{115 - 105}{10} = 1$

Step2: Apply empirical rule

The empirical rule states that for a normal distribution, approximately 68% of data lies within $\mu \pm 1\sigma$, which corresponds to z-scores -1 and 1.

Answer:

68%