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Question
quiz - gas laws
name: ebtesam
questions
- a carnival worker uses a 56.0ml pressurized helium gas cylinder to blow up balloons. if the balloons are blown up (at constant temperature) to a volume of 3.42l, the pressure of the helium inside of the balloon will be 111kpa. determine the pressure of the helium, inside the pressurized gas cylinder, expressed in the form a.bc×10^d kpa. the values of a, b, c and d are __ and __
your answer:
Step1: Apply Boyle's Law
$P_1V_1 = P_2V_2$
Step2: Convert volumes to SI - units
$V_1=56\ mL = 56\times10^{- 3}\ L$, $V_2 = 3.42\ L$, $P_2 = 111\ kPa$
Step3: Rearrange the formula for $P_1$
$P_1=\frac{P_2V_2}{V_1}$
Step4: Substitute the values
$P_1=\frac{111\ kPa\times3.42\ L}{56\times10^{-3}\ L}$
$P_1=\frac{111\times3.42}{56\times10^{-3}}\ kPa$
$P_1=\frac{379.62}{56\times10^{-3}}\ kPa$
$P_1 = 6.779\times10^{3}\ kPa$
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