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quiz 5 (id 657909) due: sat oct 4 23:59 2025. until due: 0.0 days. rest…

Question

quiz 5 (id 657909) due: sat oct 4 23:59 2025. until due: 0.0 days. restart = 0, attempt 2. question number 1. (10.00 points) given the following sampling distribution: what is p(x = 15)? 0.84 0.15 0.85 0.83 0.86 none of the above

Explanation:

Step1: Recall property of probability distribution

The sum of all probabilities in a probability - distribution is 1. Let \(P(X = 15)=p\).
We first convert the given probabilities to decimal form: \(\frac{3}{100}=0.03\), \(\frac{1}{20}=0.05\), \(\frac{1}{25}=0.04\), \(\frac{1}{25}=0.04\).

Step2: Set up the equation

The sum of probabilities \(0.03 + 0.05+0.04 + 0.04+p=1\).

Step3: Solve the equation for \(p\)

First, add the known probabilities: \(0.03+0.05 + 0.04+0.04=0.16\).
Then, \(p = 1-(0.03 + 0.05+0.04 + 0.04)=1 - 0.16=0.84\).

Answer:

0.84