quiz 3
question 1
how much chocolate ice cream is sold each hour in pickering according to the stacked bar graph below?
question 2
how many ice cream cones are sold each hour in ajax according to the stacked bar graph in question 1?
question 3
what is the mean of this data?
20, 18, 17, 13, 21, 19, 17, 22, 16, 23
question 4
what is the variance of the same data from question 3?
question 5
the distance time graph below shows the movement of road runner while trying to escape his nemesis, wile e. coyote. what is the speed of the road runner along the ab segment?
question 6
according to the distance time graph in question 5, when is the road runner going the slowest, but not at rest?

Question

Accepted Answer

### Question 1
# Explanation:
## Step1: Locate Pickering on graph
Find the bar corresponding to Pickering.
## Step2: Identify chocolate - colored part
The light - colored part of the bar represents chocolate ice - cream. Count the number of units. The number of cones of chocolate ice - cream sold each hour in Pickering is 6.
# Answer:
6

### Question 2
# Explanation:
## Step1: Locate Ajax on graph
Find the bar for Ajax.
## Step2: Sum the parts
Add the number of chocolate and vanilla parts. The bar for Ajax has 1 unit of chocolate and 9 units of vanilla, so 1 + 9=10 ice - cream cones are sold each hour in Ajax.
# Answer:
10

### Question 3
# Explanation:
## Step1: Recall mean formula
The mean $\bar{x}=\frac{\sum_{i = 1}^{n}x_{i}}{n}$, where $x_{i}$ are data points and $n$ is the number of data points.
## Step2: Calculate sum of data
$\sum_{i=1}^{10}x_{i}=20 + 18+17+13+21+19+17+22+16+23 = 186$.
## Step3: Calculate mean
$n = 10$, so $\bar{x}=\frac{186}{10}=18.6$.
# Answer:
18.6

### Question 4
# Explanation:
## Step1: Recall variance formula
The variance $s^{2}=\frac{\sum_{i = 1}^{n}(x_{i}-\bar{x})^{2}}{n - 1}$, where $\bar{x}$ is the mean and $n$ is the number of data points. We know $\bar{x}=18.6$ and $n = 10$.
## Step2: Calculate $(x_{i}-\bar{x})^{2}$ for each $x_{i}$
$(20 - 18.6)^{2}=1.96$, $(18 - 18.6)^{2}=0.36$, $(17 - 18.6)^{2}=2.56$, $(13 - 18.6)^{2}=31.36$, $(21 - 18.6)^{2}=5.76$, $(19 - 18.6)^{2}=0.16$, $(17 - 18.6)^{2}=2.56$, $(22 - 18.6)^{2}=11.56$, $(16 - 18.6)^{2}=6.76$, $(23 - 18.6)^{2}=19.36$.
## Step3: Calculate sum of $(x_{i}-\bar{x})^{2}$
$\sum_{i = 1}^{10}(x_{i}-\bar{x})^{2}=1.96+0.36+2.56+31.36+5.76+0.16+2.56+11.56+6.76+19.36 = 82.4$.
## Step4: Calculate variance
$s^{2}=\frac{82.4}{9}\approx9.16$.
# Answer:
9.16

### Question 5
# Explanation:
## Step1: Recall speed formula
Speed $v=\frac{\Delta d}{\Delta t}$, where $\Delta d$ is the change in distance and $\Delta t$ is the change in time.
## Step2: Identify $\Delta d$ and $\Delta t$ for segment AB
At point A, $d_{A}=20$ km and $t_{A}=0$ min. At point B, $d_{B}=5$ km and $t_{B}=5$ min. $\Delta d=d_{B}-d_{A}=5 - 20=- 15$ km, $\Delta t=t_{B}-t_{A}=5$ min.
## Step3: Calculate speed
$v=\frac{-15}{5}=-3$ km/min. The negative sign just indicates the direction of motion. The speed is 3 km/min.
# Answer:
3 km/min

### Question 6
# Explanation:
## Step1: Recall that slope of distance - time graph is speed
The slope of the distance - time graph gives the speed. The less steep the slope (excluding horizontal lines where speed is 0), the slower the speed.
## Step2: Analyze the graph
The segment EF has a non - zero but relatively less steep slope compared to other non - horizontal segments.
# Answer:
Segment EF

Sovi.AI - AI Math Tutor

QUESTION IMAGE

Question

Explanation:

Question 1

Step1: Locate Pickering on graph

Step2: Identify chocolate - colored part

Step1: Locate Ajax on graph

Step2: Sum the parts

Step1: Recall mean formula

Step2: Calculate sum of data

Step3: Calculate mean

Answer:

Question 2