Question

ralph rolls a single die two times in a row. what is the probability that he will roll a \three\ both times?
a (\frac{1}{3})
b (\frac{1}{18})
c (\frac{1}{36})
d (\frac{1}{6})

Explanation:

Step1: Probability of rolling a 3 once

A die has 6 faces, so the probability of rolling a 3 in one roll is $\frac{1}{6}$.

Step2: Probability of two independent events

Since the two rolls are independent, the probability of rolling a 3 both times is the product of the probabilities of each event. So we multiply the probability of rolling a 3 once by itself: $\frac{1}{6} \times \frac{1}{6} = \frac{1}{36}$.

Answer:

C. $\frac{1}{36}$