Question

rank the following travel distances and their respective travel times by their average speeds in order from the highest (top) to the lowest (bottom). instructions 2 m in 3000 seconds 9 m in 80 seconds 600 m in 3 seconds 1000 m in 1 second 50 m in 20 seconds

Explanation:

Step1: Calculate speed for each case

Average speed formula: $v = \frac{d}{t}$

1. $v_1 = \frac{2}{3000} = \frac{1}{1500} \approx 0.00067$ m/s
2. $v_2 = \frac{9}{80} = 0.1125$ m/s
3. $v_3 = \frac{600}{3} = 200$ m/s
4. $v_4 = \frac{1000}{1} = 1000$ m/s
5. $v_5 = \frac{50}{20} = 2.5$ m/s

Step2: Rank speeds from highest to lowest

Compare the calculated values: $1000 > 200 > 2.5 > 0.1125 > 0.00067$

Answer:

1. 1000 m in 1 second
2. 600 m in 3 seconds
3. 50 m in 20 seconds
4. 9 m in 80 seconds
5. 2 m in 3000 seconds