Question

an x - ray exposure is made using 320 milliamperage (ma), 0.2 seconds, 96 kilovoltage peak (kvp), and a source - to - image distance (sid) of 60 inches. what is the maximum energy of x - ray photons in the beam?
0.2 kiloelectron volts (kev)
96 kiloelectron volts (kev)
192 kiloelectron volts (kev)
320 kiloelectron volts (kev)

Explanation:

Step1: Recall energy - voltage relation

The maximum energy of x - ray photons in an x - ray beam is equal to the peak kilovoltage (kVp) used in the x - ray exposure.

Step2: Identify given kVp value

The given kVp is 96 kVp. Since 1 kVp = 1 keV for x - ray photons in terms of maximum energy, the maximum energy of x - ray photons is 96 keV.

Answer:

96 kiloelectron volts (keV)