Question

in the reaction $3\ce{cuso_{4}} + 2\ce{al} \
ightarrow \ce{al_{2}(so_{4})_{3}} + 3\ce{cu}$, how many moles of copper will be produced from 2 moles of aluminum? (for this problem, no need to show work.)

Explanation:

Step1: Analyze the stoichiometry of the reaction

From the balanced chemical equation \( 3\text{CuSO}_4 + 2\text{Al}
ightarrow \text{Al}_2(\text{SO}_4)_3 + 3\text{Cu} \), we can see that the mole ratio of aluminum (Al) to copper (Cu) is \( 2:3 \).

Step2: Calculate the moles of copper produced

We are given 2 moles of aluminum. Using the mole ratio, if 2 moles of Al react, the moles of Cu produced can be calculated as follows:
Let \( x \) be the moles of Cu.
\( \frac{2 \text{ moles Al}}{3 \text{ moles Cu}}=\frac{2 \text{ moles Al}}{x} \)
Cross - multiplying gives \( 2x = 2\times3 \), so \( x = 3 \) moles.

Answer:

3 moles