Question

read the following description of a relationship:
a columnist had already published 18 articles before joining a newspaper. since then, he has published 11 more articles every month.
let m represent the number of months since joining the newspaper and a represent the total number of articles he has published.
complete the table using the function a = 11m + 18.

m	a
3	\boxed{}
5	\boxed{}
7	\boxed{}

Explanation:

Step1: Calculate for m = 3

Substitute \( m = 3 \) into the formula \( a = 11m + 18 \).
\( a = 11\times3 + 18 \)
\( = 33 + 18 \)
\( = 51 \)

Step2: Calculate for m = 5

Substitute \( m = 5 \) into the formula \( a = 11m + 18 \).
\( a = 11\times5 + 18 \)
\( = 55 + 18 \)
\( = 73 \)

Step3: Calculate for m = 7

Substitute \( m = 7 \) into the formula \( a = 11m + 18 \).
\( a = 11\times7 + 18 \)
\( = 77 + 18 \)
\( = 95 \)

Answer:

For \( m = 3 \), \( a = 51 \); for \( m = 5 \), \( a = 73 \); for \( m = 7 \), \( a = 95 \)

So the completed table is:

\( m \)	\( a \)
3	51
5	73
7	95