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a rectangle has an area of 102 cm². the length of the rectangle is 17 c…

Question

a rectangle has an area of 102 cm². the length of the rectangle is 17 cm. what is the perimeter of the rectangle? enter your answer in the box. cm

Explanation:

Step1: Find the width of the rectangle

We know that the area formula of a rectangle is $A = l\times w$, where $A$ is area, $l$ is length and $w$ is width. Given $A = 102\ cm^{2}$ and $l=17\ cm$, we can find $w$ by $w=\frac{A}{l}$. So $w=\frac{102}{17}=6\ cm$.

Step2: Calculate the perimeter of the rectangle

The perimeter formula of a rectangle is $P = 2(l + w)$. Substitute $l = 17\ cm$ and $w = 6\ cm$ into the formula: $P=2\times(17 + 6)=2\times23 = 46\ cm$.

Answer:

46