Question

1. $x^{2}(x^{4})=$

(a) $x^{6}$
(b) $x^{8}$
(c) $2x^{6}$
(d) $2x^{8}$

1. if a rectangle has a perimeter of 36 feet and is

4 feet wide, whats its area?
(a) 56 square feet
(b) 128 square feet
(c) 112 square feet
(d) 16 square feet

1. factor

(a) $($x
(b) $($x
(c) $($x
(d) $($x

1. $(3×2)$

of x?
(a) -$
(b) 5
(c) 10
(d) 1

1. solve

Explanation:

Step1: Apply exponent product rule

When multiplying terms with the same base, add exponents: $x^a \cdot x^b = x^{a+b}$.
$x^2(x^4) = x^{2+4} = x^6$

Step2: Recall rectangle perimeter formula

Perimeter $P = 2(l + w)$, solve for length $l$.
Given $P=36$, $w=4$:
$36 = 2(l + 4)$
$\frac{36}{2} = l + 4$
$18 = l + 4$
$l = 18 - 4 = 14$

Step3: Calculate rectangle area

Area $A = l \times w$.
$A = 14 \times 4 = 56$

Answer:

1. A) $x^6$
2. A) 56 square feet