Question

the redox reaction given below occurs in basic solution. teo₃⁻² + n₂o₄ → te + no₃⁻ balance the half - reaction: teo₃⁻² → te how many electrons are transferred? ?e⁻

Explanation:

Step1: Determine oxidation state of Te

In \( \text{TeO}_3^{2 -} \), let oxidation state of Te be \( x \). Oxygen has oxidation state -2. So, \( x + 3\times(-2)= - 2 \), solving gives \( x = + 4 \). In Te (elemental), oxidation state is 0.

Step2: Calculate electron transfer

The change in oxidation state of Te is from +4 to 0. So, each Te atom gains \( 4 - 0 = 4 \) electrons. Since there's 1 Te atom in the half - reaction \( \text{TeO}_3^{2 -}\to\text{Te} \), the number of electrons transferred is 4.

Answer:

4